The vertex of the function's graph is given. Find c. y = - 3x2 + 6x + c; (1, 0)

Vertex form of a parabola is:

y = a (x - h) ^2 + k

Where vertex (h, k) is given to be (1,0) and x terms are factorable by "a" = - 3

y = - 3 (x-1) ^2 + 0

expand the parenthesis

y = - 3 (x-1) (x-1)

y = - 3 (x^2 - x - x + 1)

multiply - 3 through parenthesis

y = - 3x^2 + 6x - 3

Compare to given equation

c = - 3