A jar contains a combination of 60 nickels and dimes worth a total of $4.30. suppose that is deemed desirable to determine how many of each kind of coin are in the jar.

We will represent everything in cents

nickles are worth 5 cents and dimes are 10 cents

n=number of nickles

d=number of dimes

60 total coins

n+d=60

total is 430 cents

5n+10d=430

divide both sides by 5

n+2d=86

we gots

n+d=60 and

n+2d=86

eliminate

multiply first equation by - 1 and add to 2nd equation

-n-d=-60

n+2d=86 +

0n+1d=26

d=26

so

n+d=60

n+26=60

n=34

34 nickles and 26 dimes