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25 December, 10:19

Consider the expression 2√ 3 cos (x) csc (x) + 4cos (x) - 3csc (x) - 2 √ 3 This expression can be represented as the product of the factors ...

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  1. 25 December, 13:00
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    The answer:

    let be A (x) = 2√ 3 cos (x) csc (x) + 4cos (x) - 3csc (x) - 2 √ 3

    this function can be represented as the product of the factors

    proof

    2√ 3 cos (x) csc (x) + 4cos (x) - 3csc (x) - 2 √ 3 =

    2√ 3 cos (x) csc (x) + 4cos (x) csc (x) / csc (x) - 3csc (x) - 2 √ 3 csc (x) / csc (x)

    this method doesn't change nothing inside the function A (x)

    so we have

    [ 2√ 3 cos (x) + 4cos (x) / csc (x) - 3 - 2 √ 3 / csc (x) ]. csc (x) this is a product of two factors,

    [ 2√ 3 cos (x) + 4cos (x) / csc (x) - 3 - 2 √ 3 / csc (x) ] and csc (x)

    for more explanation

    A (x) = [ 2√ 3 cos (x) - 3 + (4cos (x) - 2 √ 3) / csc (x) ]. csc (x)
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