The radioisotope Phosphorus-32 is used in leukemia therapy. The half-life of this isotope os 14.26 days. Which equation determines the percent of an initial amount of the isotope remaining after t days?

A = 14.26 (1/2) ^100/t

A = 14.26 (1/2) ^t/100

A = 100 (1/2) ^14.26/t

A = 100 (1/2) ^t/14.26

Question

Judah Johns

27 February, 13:52

+4

Answers (1)

Know the Answer?

Dylan Cole · Answer 1

The remaining value = the initial value * (1/2) ^ (t/T), t is the number of years, T is half life.

So D is the right answer.

The radioisotope Phosphorus-32 is used in leukemia therapy. The half-life of this isotope os 14.26 days. Which equation determines the percent of an initial amount of the isotope remaining after t days?A = 14.26 (1/2) ^100/tA = 14.26 (1/2) ^t/100A = 100 (1/2) ^14.26/tA = 100 (1/2) ^t/14.26