Ask Question
27 February, 13:52

The radioisotope Phosphorus-32 is used in leukemia therapy. The half-life of this isotope os 14.26 days. Which equation determines the percent of an initial amount of the isotope remaining after t days?

A = 14.26 (1/2) ^100/t

A = 14.26 (1/2) ^t/100

A = 100 (1/2) ^14.26/t

A = 100 (1/2) ^t/14.26

+4
Answers (1)
  1. 27 February, 16:16
    0
    The remaining value = the initial value * (1/2) ^ (t/T), t is the number of years, T is half life.

    So D is the right answer.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The radioisotope Phosphorus-32 is used in leukemia therapy. The half-life of this isotope os 14.26 days. Which equation determines the ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers