Ask Question
31 January, 17:49

Suppose an architect has a drawing of a project he is building. The drawing is 8 wide long by 10 inches long. The finished structure is 64 feet wide by 80 feet long. How many times larger is the actual structure than the drawing?

+2
Answers (2)
  1. 31 January, 19:23
    0
    It is 8 times larger, 8x8=64 and 8x10=80 which is the current length and width of the finished structure
  2. 31 January, 19:38
    0
    It’s larger by two widths because 8x8 = 64 8x10 = 80
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose an architect has a drawing of a project he is building. The drawing is 8 wide long by 10 inches long. The finished structure is 64 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers