A city us growing at the rate of 0.9% annually. if there were 3619000 residents in yhe city in 1994, find how many to the nearest ten thousand are living in that city in 2000. use y=3619000 (2.7) ^0.009t

For this case we have the following equation:

y = 3619000 (2.7) ^ 0.009t

We must evaluate the equation for the year 2000.

Therefore, we must replace the following value of t:

t = 2000 - 1994

t = 6

Substituting we have:

y = 3619000 (2.7) ^ (0.009 * 6)

y = 3818407.078

Round to the nearest ten thousand:

y = 3820000

Answer:

3820000 residents are living in that city in 2000