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31 January, 00:11

Find 4 consecutive integers such that if the sum of the first and third is increased by 10 the result is 6 greater than 4 tiems the fourth

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  1. 31 January, 01:05
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    The 4 consecutive integers will be x, x=1, x+2, and x+3

    x+x+2+10 = 4 (x+3) + 6

    2x+12=4x+18

    -6 = 2x

    x=-3

    the 4 numbers are - 3, - 2, - 1, 0
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