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8 October, 10:04

Excluded values for y=5 / (6x-72)

(the / is a fraction so its 5 over 6x)

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  1. 8 October, 13:58
    0
    The denominator cannot equal zero. Set the expression on the denominator = to zero to find the value that must be excluded.

    6x - 72 = 0

    add 72 to both sides

    6x = 72

    Divide both sides by 6

    x = 9

    The excluded value is 9.
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