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6 September, 20:10

Wo systems of equations are shown below. The first equation in System B is the original equation in system A. The second equation in System B is the sum of that equation and a multiple of the second equation in System A. A. x + 3y = 11 → x + 3y = 11 5x - y = 17 → 15x - 3y = 51 15x = 62 B. x + 3y = 11 15x = 62 What is the solution to both systems A and B?

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  1. 6 September, 20:34
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    A.)

    x + 3y = 11

    5x - y = 17 ⇒ 15x - 3y = 51

    15x = 62

    B.) x + 3y = 11

    15x = 62

    x + 3y = 11

    5x - y = 17

    x = 11 - 3y

    5x - y = 17

    5 (11-3y) - y = 17

    55 - 15y - y = 17

    -16y = 17 - 55

    -16y = - 38

    y = - 38/-16

    y = 2.375

    x = 11 - 3y

    x = 11 - 3 (2.375)

    x = 11 - 7.125

    x = 3.875

    x = 3.875; y = 2.375

    x + 3y = 11

    3.875 + 3 (2.375) = 11

    3.875 + 7.125 = 11

    11 = 11
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