Ask Question
21 May, 04:16

Find (gOf) (x)

f (x) = x^2 - (1/2x) + 4

g (x) = 8x-2

+4
Answers (2)
  1. 21 May, 06:05
    0
    F (x) = x^2 - (1/2) x+4

    g (x) = 8x-2

    (g o f) (x) = ?

    (g o f) (x) = g (f (x)) = g (x^2 - (1/2) x+4)

    x=x^2 - (1/2) x+4→g (x^2 - (1/2) x+4) = 8[x^2 - (1/2) x+4]-2

    g (x^2 - (1/2) x+4) = 8x^2-4x+32-2

    g (x^2 - (1/2) x+4) = 8x^2-4x+30

    Answer: (g o f) (x) = 8x^2-4x+30
  2. 21 May, 06:29
    0
    For this case, the first thing we must do is the composition of functions.

    We have:

    f (x) = x ^ 2 - (1 / 2x) + 4

    g (x) = 8x-2

    (gOf) (x) = 8 (x ^ 2 - (1 / 2x) + 4) - 2

    We rewrite: now the function:

    (gOf) (x) = 8x ^ 2 - (8/2) x + 32-2

    (gOf) (x) = 8x ^ 2-4x + 30

    Answer:

    The final result is:

    (gOf) (x) = 8x ^ 2-4x + 30
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find (gOf) (x) f (x) = x^2 - (1/2x) + 4 g (x) = 8x-2 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers