S the expression x3•x3•x3 equivalent to x3•3•3

Remember

(x^m) (x^n) = x^ (m+n)

and difference of 2 perfect squres

(a²-b²) = (a-b) (a+b)

and sum or difference of 2 perfect cubes

so

(x^3) (x^3) (x^3) = x^ (3+3+3) = x^9

so

x^9=3*3*x^3

x^9=9x^3

minus 9x^3 both sides

0=x^9-9x^3

factor

0 = (x^3) (x^6-9)

factor difference of 2 perfect squraes

0 = (x^3) (x^3-3) (x^3+3)

factor differnce or sum of 2 perfect cubes (force 3 into (∛3) ³)

0 = (x³) (x-∛3) (x²+x∛3+∛9) (x+∛3) (x²-x∛3+∛9)

set each to zero

x³=0

x=0

x-∛3=0

x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0

x=-∛3

x²-x∛3+∛9=0 has no solution

so the solutions are

x=-∛3, 0, ∛3