The square root of a number is subtracted from the sum of the number and 12. the result is 42. what is the original number?

Question

Mathematics

Precious Hays

3 February, 12:56

The square root of a number is subtracted from the sum of the number and 12. the result is 42. what is the original number?

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Answers (1)

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Bridget · Answer 1

x + 12 - sqrt (x) = 42

-sqrt (x) = - x+30

-sqrt (x) ^2 = (-x+30) ^2

x^2 - 61x + 900 = 0

(x-36) (x-25) = 0

x = 36

36+12 = 48 - sqrt (36) = 48-6 = 42

X = 36