Find the magnitude and direction angle for the vector v = 3 cos 123°i + 3 sin 123°j.

A. 3√2, 57°

B. 3√2, 123°

C. 3, 57°

D. 3, 123°

The vector written in its generic form is given by:

v = lvl cos theta ° i + lvl without theta ° j

Where.

lvl: magnitude of the vector

theta: angle of the vector with respect to the x axis.

For this case we have the following vector:

v = 3 cos 123 ° i + 3 without 123 ° j

Where,

lvl = 3

theta = 123 °

Answer:

The magnitude and direction angle for the vector v is:

D. 3, 123 °