Consider the function f (x) = ^2+2x-15. What are the x-intercepts of the function

To find the x-intercepts of the function, use the quadratic formula:

(-b± √ (b^2-4ac)) / 2a

Plug in the values of the function x^2+2x-15 and note that the a value is 1, the b value is 2, and the c value is - 15:

(-2± √ (2^2-4 (1) (-15))) / 2 (1)

When simplified you should get:

(-2 ± √64) / 2

Then, when you simplify further, you get two fractions:

6 / 2 and - 10/2

These fractions simplify to your two values of x which are 3 and - 5 which would be your x-intercepts,

(3,0) and (-5,0)