What values for θ (0 ≤ θ ≤ 2pie) satisfy the equation?

2 sin θ cos θ + Sqr3 cos θ = 0

a.) pie/2, 4pie/3, 3pie/2, 5pie/3

b.) pie/2, 3pie/4, 3pie/2, 5pie/3

c.) pie/2, 3pie/4, 3pie/2, 5pie/4

d.) pie/2, pie/4, 3pie/2, 5pie/3

Factor out the cos θ:

cosθ (2sin θ + sqrt3) = 0

Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin θ + sqrt3) = 0

The first case, cosθ = 0 only at θ = pi/2, 3pi/2.

The second case, (2sin θ + sqrt3) = 0 simplifies to:

sin θ = (-sqrt3) / 2

θ = 4pi/3, 5pi/3

Therefore the answer is A.