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11 February, 19:20

Simplify i22. possible choices are 1, - 1, i,-i

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  1. 11 February, 21:20
    0
    The answer to this question is 1
  2. 11 February, 21:31
    0
    I assume you mean i^22

    There’s a cycle i follows when being taken to a certain power, so let’s see what that is:

    i^1 = i

    i^2 = - 1

    i^3 = - i

    i^4 = 1

    And i^5 = i, so our cycle repeats after every 4th power. To find i^22 then, we can divide 22 by 4 to obtain an answer of 5, with a remainder of 2. In other words, 22 = 4 (5) + 2

    So, i^22 = i^[4 (5) + 2]

    We can break that up into the product i^[4 (5) ] x i^2

    We know that i^4 is 1, and 1^5 is still 1, so i^[4 (5) ] = 1; i^2 is simply - 1, so altogether, we find that

    i^[4 (5) ] x i^2 = 1 x (-1) = - 1

    Our answer then is - 1.
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