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21 June, 06:59

Which is the equation of a parabola with vertex (0, 0), that opens downward and has a focal width of 6?

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  1. 21 June, 08:43
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    Vertex: V = (0,0) = (h, k) →h=0, k=0

    Opens downward:

    (x-h) ^2=4p (y-k)

    Width focal: p=-6<0 (donwnward)

    Replacing h=0, k=0 and p=-6 in the equation above:

    (x-0) ^2=4 (-6) (y-0)

    x^2=-24y

    Answer: The equation of the parabola is x^2=-24y
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