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14 August, 06:17

Find the center and radius of a circle defined by the equation x^2+yy^2+4x-8y+13=0

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  1. 14 August, 10:09
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    Hello:

    x²+y²+4x-8y + 13 = 0

    (x² + 4x) + (y² - 8y) + 13 = 0

    (x²+4x+4) - 4 + (y-8y + 16) - 16 + 13 = 0

    (x+2) ² + (y - 4) ² = 7

    the center is : (-2, 4) and radius √7
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