During a particular baseball season, a team averaged 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of 9,440 per game. what is the probability that a randomly selected game during the season had an attendance greater than 50,000 people?

Question

Mathematics

Zachery Moon

28 July, 06:42

During a particular baseball season, a team averaged 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of 9,440 per game. what is the probability that a randomly selected game during the season had an attendance greater than 50,000 people?

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Answers (1)

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Norman · Answer 1

Given:

μ = 41,602, the mean

σ = 9,440, the standard deviation.

For the random variable x = 50,000, the z-score is

z = (x - μ) / ο = (50,000 - 41,602) / 9,440 = 0.8896

From standard tables, obtain

P (x > 50,000) = 0.08132 or 81.32%

Answer: 0.8132