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5 May, 18:02

What is the step by step way to solve this exponential equation?2^ (x+1) = 3^x

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  1. 5 May, 21:51
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    2 (ˣ⁺¹) = 3ˣ

    ln[2 (ˣ⁺¹) ] = ln (3ˣ)

    (x+1). ln (2) = x. ln (3)

    Expand:

    x. ln (2) + ln (2) = x. ln (3)

    x. ln (2) - x. ln (3) = - ln (2)

    x[ln (2) - ln (3) ] = - ln (2)

    x = [ - ln (2) ] / [ln2) - ln (3)

    And x = 1.7095
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