The condition proves that ∆ABC and ∆EFG are congruent by the SAS criterion.

If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G.

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9 February, 23:14

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Landen Wilkerson · Answer 1

If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G are not equal:

angle C ≠ angle G

The condition proves that ∆ABC and ∆EFG are congruent by the SAS criterion.If AB ≠ EF, the criterion for congruency is violated. In this situation, angle C angle G.