When fritz drives to work his trip takes 48 minutes, but when he takes the train it takes 40 minutes. find the distance fritz travels to work if the train travels an average of 6 miles per hour faster than his driving. assume that the train travels the same distance as the car?

Let x be the speed when Fritz is driving

x + 6 will be the train speed

Converting minutes to hrs

48 mins = 48/60 = 4/5 hrs

40 mins = 40/60 = 2/3 hrs

Remember formula distance = rate * time

distance driving = (4/5) x

distance train traveling = (2/3) (x+6)

The train travels the same distance as the car

4/5x = 2/3 (x+6)

4/5x = 2/3x + 4

4/5x - 2/3x = 4

basic elementary school math

2/15x = 4

2x = 40

x = 30 miles/hrs is the speed he driving.

distance train traveling = 2/3 (30 + 6) = 24 miles

check with the distance he driving

4/5 (30) = 24 miles