How to find the inverse of h (x) = 3 / - x - 2 List steps.

To find the inverse,

First, you would have to switch the domain and range. In other words, swap x and y:

h (x) = 3 / - x-2

y = 3 / - x-2

x = 3 / - y-2

Then, when you have this, simply solve for y:

x = 3/-y-2

x (-y-2) = 3/-y-2 (-y-2)

x (-y-2) / x = 3 / x

-y-2 = 3/x

-y = 3/x + 2

y = - 3/x - 2

So the inverse would be

h⁻¹ (x) = - 3/x - 2