If f (x) = 2x^3 - 3x + 1 find f (3)

Okay so what f (3) is saying is that x=3. You have to plug three in for x to make the new equation of 2 (3) ^3-3 (3) + 1 next you would do pemdas which is parethesis then exponets then multiplication/division then addition/subtraction to get 2*3=6 6^3 is 216 216-3*3 is 207 207+1 is 208 so the answer is f (3) = 208