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31 May, 16:51

Find the sum of the first 50 terms. - 6,-2,2,6 ...

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  1. 31 May, 17:44
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    This is an arithmetic sequence with a1 = - 6 and d = 4

    Sn = (n/2) (2a1 + (n-1) d)

    S50 = (50/2) [2*-6 + (50-1) * 4]

    = 25 * (-12 + 4*49)

    = 4600
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