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14 December, 12:49

The perimeter is 110 in. The length of the rectangle is 4 times as long as the width. what is the width of the rectangle? ill make you brainliest if you showed your work or how you did it.

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  1. 14 December, 14:22
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    To start, let's define our variable, which is x. x will represent the width of the rectangle. Next, since you know that the length is 4 times as long as the width, it will be represented by 4x. Now, since you know that the perimeter of a figure is the sum of the length of all the sides of the rectangle, you can express the perimeter with this expression: 4x+4x+x+x

    Then, you set the expression to the perimeter, which is 110.

    4x+4x+x+x=110

    Combine like terms: 10x=110

    And solve for x: x=11

    Now that you have solved for x, which represents the width of the rectangle, you now know that your answer is 11.
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