Suppose the equation ax^2+bx+c=0 has no real solution and a graph of the related function has a vertex that lies in the second quadrant.
Is the value of "a" positive or negative? Explain your reasoning.
Suppose the graph is translated so the vertex is in the fourth quadrant. Does the graph have any x-intercepts? Explain.
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Home » Mathematics » Suppose the equation ax^2+bx+c=0 has no real solution and a graph of the related function has a vertex that lies in the second quadrant. Is the value of "a" positive or negative? Explain your reasoning.