Solve the system below.

y = x^2 - 4

y = - 4

a. 0, - 4

b. - 4, 0

c. (0, - 4), (-4, 0)

d. there is no real solution

Question

Mathematics

Reece Bridges

27 April, 13:33

Solve the system below.

y = x^2 - 4

y = - 4

a. 0, - 4

b. - 4, 0

c. (0, - 4), (-4, 0)

d. there is no real solution

+4

Answers (1)

Know the Answer?

Danna Blanchard · Answer 1

To solve this system, let y = x^2 - 4 = - 4. Then y = x^2. This is true for all x. There is no single numerical solution. y = x^2 is a function with infinitely many inputs/outputs.

Solve the system below.y = x^2 - 4y = - 4a. 0, - 4b. - 4, 0c. (0, - 4), (-4, 0)d. there is no real solution

Solve the system below.

y = x^2 - 4

y = - 4

a. 0, - 4

b. - 4, 0

c. (0, - 4), (-4, 0)

d. there is no real solution