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27 April, 13:33

Solve the system below.

y = x^2 - 4

y = - 4

a. 0, - 4

b. - 4, 0

c. (0, - 4), (-4, 0)

d. there is no real solution

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Answers (1)
  1. 27 April, 13:43
    0
    To solve this system, let y = x^2 - 4 = - 4. Then y = x^2. This is true for all x. There is no single numerical solution. y = x^2 is a function with infinitely many inputs/outputs.
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