If m2 = 7x + 7, m3 = 4y, and m4 = 112, find the values of x and y

M2 x 2 = m4

soo m2 now becomes m4 = 14x + 14

112 = 14x + 14

subtract 14 from both sides

98 = 14x

divide by 14 on both sides

7 = x

to find Y, 12 is the lowest number you can make 3 & 4

so multiply m3 by 4 and m4 by 3

so instead of m3 = 4y and m4 = 112 it now becomes

m12 = 16y and m12 = 336

16Y = 336

divide both sides by 16

Y = 21