Three zeroes in a fifth degree polynomial function are 1/3,4-61, and - 2+11i

What are the remaining zeroes of the function?

4+6i,-2-11i

-1/3,4+6i, 2+11i

-4+6i, 2-11i

3, 4+6i,-2-11i

The degree of the polynomial is 5, therefore are 5 zeros (real or imaginary).

The given zeros are

1/3, 4 - 6i, and - 2 + 11i.

Because complex zeros always occur as conjugate pairs, the remaining complex zeros are

4 + 6i and - 2 - 11i.

Answer: 4 + 6i, - 2 - 11i.