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11 December, 21:17

What is the factored version of 8-r^3

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  1. 11 December, 23:00
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    The answer to your question is (2-r) (4+2r+r^2)
  2. 11 December, 23:52
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    To factor a cube (a^3-b^3) = (a-b) (a^2+ab+b^2)

    8 is the cube of 2

    r^3 is the cube of r.

    So, a is 2 and b is r

    (2-r) (2^2+2r+r^2)

    (2-r) (4+2r+r^2)
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