The perimeter of a rectangle is 496 ft the length is 20 ft longer than the width find the area of the rectangle

P = 2 (L + W)

P = 496

L = W + 20

496 = 2 (W + 20 + W)

496 = 2 (2W + 20)

496 = 4W + 40

496 - 40 = 4W

456 = 4W

456/4 = W

114 = W

L = W + 20

L = 114 + 20

L = 134

the area ... A = L * W

A = 134 * 114

A = 15276 square ft < = = or 15276 ft^2

This might be different from someone else's calculations if i got it wrong but using substitution i found the width to be 114 ft and length to be 134 ft. multiply those together and you get A=15276 ft.