Solve the following addition and subtraction problems. a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam b. 5 sq. km 95 ha 8,994 sq. m + 11 sq. km. 11 ha 9,010 sq. m. c. 44 m - 5 dm d. 73 km 47 hm 2 dam - 11 km 55 hm

As a general rule to solve the problem we are going to transform all values to the lower unit.

a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam

3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m

b. 5 sq. km 95 ha 8,994 sq. m + 11 sq. km. 11 ha 9,010 sq. m.

5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq

9,010 sq m

5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m

c. 44 m â€" 5 dm

44 m - 0.5 m = 43.5 m

d. 73 km 47 hm 2 dam - 11 km 55 hm

73,000 m 4,700 m 20 m - 11,000 m 5,500 m

77,720 m - 16,500 m = 61,220 m