Raphael graphed the functions g (x) = x + 2 and f (x) = x - 1. How many units below the y-intercept of g (x) is the y-intercept of f (x) ?

Question

Mathematics

Calvin

14 December, 03:56

Raphael graphed the functions g (x) = x + 2 and f (x) = x - 1. How many units below the y-intercept of g (x) is the y-intercept of f (x) ?

+1

Answers (1)

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Toby · Answer 1

These functions are in the form y=mx+b

Therefore, we know that in g (x) = x+2, the y-intercept is 2.

For f (x) = x-1, the y-intercept is - 1.

Now find the difference between them.

2 - (-1) = 3

The y-intercept for f (x) is 3 units below g (x)