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4 December, 18:00

Find x such that x - 4, x, and 3x - 8 are three consecutive terms in a geometric sequence

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  1. 4 December, 19:13
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    In a geometric sequence dividing any term by the term before it yields the common multiplier.

    Then x / (x+8) = (3x-8) / x

    Solving for x: reduces to x^2-10x + 16 factor into (x-2) (x-8)

    Then x = 2 or 8

    2 produces a sequence of - 2, 2, - 2 ...

    8 produces a sequence of 4, 8, 16 ...
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