Ask Question
31 August, 01:43

A baseball team consists of nine players. How many different batting orders are possible? How many are possible if the pitcher bats last?

+2
Answers (1)
  1. 31 August, 05:08
    0
    Since the pitcher bats last, there is only one choice for the 9th slot. For the 1st slot, there are 8 choices remaining. For the 2nd slot, there are 7 choices remaining, etc.

    So the number of possible batting orders is:

    8*7*6*5*4*3*2*1 = 8! = 40,320
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A baseball team consists of nine players. How many different batting orders are possible? How many are possible if the pitcher bats last? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers