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31 July, 09:25

2. The equation h (t) = - 16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

What is the initial velocity when the rock is thrown?

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  1. 31 July, 13:10
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    For this case we have an equation of the form:

    h (t) = - (1/2) * a * t ^ 2 + vo * t + h0

    Where,

    vo: initial speed

    a: acceleration:

    h0: initial height.

    We have the following equation:

    h (t) = - 16t2 + 19t + 110

    Therefore, the initial velocity is:

    vo = 19 feet / s

    Answer:

    The initial velocity when the rock is thrown:

    vo = 19 feet / s
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