What is the equation of the line of the axis of symmetry of the quadratic function, y=3x^2-x+2?

A) x = - 3/2

B) x = - 1/6

C) x=1/6

D) x=3/2

Y=3x^2-x+2

Find when the velocity, dy/dx, is equal to zero, this value of x will represent the axis of symmetry for a quadratic because all quadratics have a constant acceleration, and thus when dy/dx=0, y (x), is at either a global maximum or minimum ...

dy/dx=6x-1

6x-1=0

6x=1

x=1/6

So the vertical line x=1/6 is the axis of symmetry.