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21 August, 17:29

If h (x) = 3x-1 and j (x) = - 2, solve h[j (2) ]

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  1. 21 August, 19:20
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    To do this we figure out the inner first. This is easy since it is j and j is always - 2. Now we can plug - 2 into h

    3 (-2) - 1=-7
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