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10 July, 06:50

Warmliquid corp., a manufacturer of water heaters, produces 30 water heaters per week. past records indicate that 10% of total water heaters produced in a week are likely to be defective. suppose a quality check was conducted on a sample of six water heaters. what is the probability that four out of six water heaters will be defective?

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  1. 10 July, 09:08
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    Let us use the Binomial Probability:

    P = nCr * p^r * q^ (n - r)

    where,

    n = total samples = 6

    r = defective samples = 4

    p = chance of defective = 10% = 0.10

    q = 1 - p = 0.90

    Solving for P:

    P = 6C4 * 0.10^4 * 0.90^2

    P = 1.215 x 10^-3 = 0.1215%

    Only 1.215 x 10^-3 or 0.1215% chance that 4 out of 6 will be defective.
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