The graph below shows four straight lines, P, Q, R, and S: graph of line P going through ordered pairs negative 2, negative 5 and 0, 3. Graph of line Q going through ordered pairs negative 1, negative 2 and 1, 6. Graph of line R going through ordered pairs negative 1, negative 4 and 1, 4. Graph of line S going through ordered pairs 0, negative 3 and 2, 5 Which line is represented by the function f (x) = 4x - 3?

Let m be the slope m = (y₂-y₁) / (x₂-x₁) and y-y₁=m (x-x₁)

p: (2,-5) and (0,3)

m = (3+5) / (0-2) = 8/-2 = - 4 slope doesn't match.

q: (-1,-2) and (1,6)

m = (6 - (-2)) / (1 - (-1)) = 8/2=4

y+2=4 (x+1)

y+2=4x+4

y=4x+2, not the equation.

r: (-1,-4) and (1,4)

m = (4 - (-4) / (1 - (-1) = 4

y - (-4) = 4 (x - (-1))

y=4x not the equation

s: (0,-3) and (2,5)

m = (5 - (-3)) / (2) = 4

y - (-3) = 4 (x-0)

y+3=4x

y=4x-3 so graph S is f (x) = 4x-3