Find 3 consecutive even integers if their sum decreased by 10 equals - 22

Three consecutive even integers can be represented by x, (x+2), and (x+4).

(x + (x + 2) + (x + 4)) - 10 = - 22 Get rid of the parentheses

x + x + 2 + x + 4 - 10 = - 22 Combine like terms (x + x + x) and (2 + 4 - 10)

3x - 4 = - 22 Add 4 to both sides

3x = - 18 Divide

x = - 6

Check you work.

x = - 6

x + 2 = - 4

x + 4 = - 2

(-6 - 4 - 2) - 10 = 22

-12 - 10 = - 22

So, your three integers are - 6, - 4, and - 2.