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5 March, 07:43

Does subtraction exhibit a property of closure over the set of real numbers? Is subtraction commutative? If not, give an example to demonstrate.

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  1. 5 March, 10:06
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    Subtraction exhibit a property of closure over the set of real numbers because if you subtract two numbers from the real numbers set, the result will still be a real number.

    Example:

    Let RS be a set of real numbers.

    RS = {1, 2, 3}

    Suppose I get 3 and subtract 1, 3 - 1, the result is 2 which is a real number. We can try a non-commutative 1 - 3 and yet it will still give us a real number which is - 2.

    Subtraction is non-commutative because if we interchange numbers in subtraction, the result will either be positive or negative.

    Example:

    3 - 1 = 2. The answer is 2; but we can not say this is true for 1 - 3 because it will yield - 2.
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