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7 June, 17:11

John received change worth $13. He received 10 more dimes than nickels and 22 more quarters than dimes. How many coins of each did he receive?

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  1. 7 June, 18:54
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    If the amount of money in dimes is 10d (since there are 10 cents per dime and with d being the number of dimes), the amount of money in nickels is 5n and the amount in quarters is 22q (if n=the number of nickels and q=the number of quarters), we can write 10d+5n+25q=1300 (since 1300 cents=13 dollars). In addition, the number of nickels is d-10 (since n+10=d, subtract 10 from both sides to get d-10=n) and the number of quarters is 22+d. Substituting those in, 10d+5 (d-10) + 25 (d+22) = 10d+5d-50+25d+550=40d+500=1300. Subtracting 500 from both sides, we get 800=40d. Next, we divide both sides by 40 to get d=800/40=20. Next, since n=d-10, 20-10=10=n. In addition, since d+22=q, 20+22=42=q.
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