If a right triangle has a leg that measures 24 and a hypotenuse that measures 25. what is the length of the other leg?

Hypotenuse ^2 = leg1 ^2 + leg2 ^2

25^2 = 24^2 + leg2 ^2

leg2 ^2 = 25^2-24^2 = 625 - 576=49

⇒ leg = V49

⇒ leg = 7

Phytagoras' Theorem states that in any right triangle, the square of the hypotenuse is equal to the sum of the squares of the two legs. If c represents the hypotenuse, a and b represent the two leg, the theorem could be written as below.

c² = a² + b²

a² + b² = c

From the question, we could get information that

c = 25

a = 24

and we should find the value of b

Plug in the numbers to the formula

a² + b² = c²

24² + b² = 25²

576 + b² = 625

b² = 625 - 576

b² = 49

b = √49

b = 7

The length of the other leg is 7