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22 April, 03:37

Noelle stands at the edge of a cliff and drops a rock. The height of the rock, in meters, is given by the function f (x) = - 4.9x2+17, where x is the number of seconds after Noelle releases her rock.

Cesar, who is standing nearby on the ground, throws a rock straight up in the air. The height of Cesar's rock, in meters, is given by the function g (x) = - 4.9x2+13x, where x is the number of seconds after he releases his rock.

There is a moment when the rocks are at the same height.

What is this height?

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Answers (1)
  1. 22 April, 06:04
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    For this case what we must do is to equal both functions at the moment in which it is to find the result.

    We have then:

    f (x) = g (x)

    -4.9x2 + 17 = - 4.9x2 + 13x

    Clearing x we have:

    17 = 13x

    x = 17/13

    x = 1.31 s

    Then, to find the height, with respect to the floor we have:

    g (1.31) = - 4.9 * (1.31) ^ 2 + 13 * (1.31)

    g (1.31) = 8.62

    Answer:

    The height with respect to the ground is:

    8.62 m
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