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11 May, 19:50

Three consecutive multiples of 3 have a sum of 36.

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  1. 11 May, 23:44
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    Charstar Ambitious 36 = x+y+z

    In terms of x:

    x=x

    y=x+3

    z=x+6

    36 = x+x+3+x+6

    36=3x+9

    27=3x

    x=9

    9+6=15

    The largest is 15
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