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8 October, 10:50

Is it possible to build a triangle using the given side lengths? if so, list the angles of the triangle in order from least to greatest measure. PQ=sqrt (58), QR=2sqrt (13), PR=5sqrt (2)

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  1. 8 October, 11:21
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    To build a triangle we need that the sum of any two given sides to be greater than the third side.

    PQ+QR=

    sqrt (58) + 2sqrt (13) = 14.82687566 >PR ✅

    QR+PR=

    2sqrt (13) + 5sqrt (2) = 14.28217036 >PQ✅

    PQ+PR=

    Sqrt (58) + 5sqrt (2) = 14.68684092>QR✅

    So YES we can make a triangle with those dimensions

    The least angle will be opposing the least side so will have

    Angle PQR, angleQPR, angleQRP

    Q

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    P - - R
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