If the area of a rectangle is 24a^2b and the length is 8ab^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

Question

Mathematics

Ari Watson

26 December, 01:22

If the area of a rectangle is 24a^2b and the length is 8ab^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

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Answers (1)

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Gloria Molina · Answer 1

Set up the formula for area of a rectangle. The formula is {/displaystyle A = (l) (w) }, where {/displaystyle A}equals the area of the rectangle, {/displaystyle l} equals the length of the rectangle, and {/displaystyle w} equals the width of the rectangle.[1] This method will only work if you are given the area and length of the rectangle. You might also see the formula written as {/displaystyle A = (h) (w) }, where {/displaystyle h} equals the height of the rectangle and is used instead of length.[2] These two terms refer to the same measurement.

Plug the values for area and length into the formula. Make sure you substitute for the correct variables. For example, if you are trying to find the width of a rectangle that has an area of 24 square centimeters, and a length of 8 centimeters, your formula will look like this:

Solve for {/displaystyle w}. To do this, you need to divide each side of the equation by the length. For example, in the equation {/displaystyle 24=8w}, you would divide each side by 8.

{/displaystyle 24=8w}

Write your final answer. Don’t forget to include the unit of measurement. For example, for a rectangle with an area of {/displaystyle 24cm^{2}} and a length of {/displaystyle 8cm}, the width would be {/displaystyle 3cm}.