Y=2x+8 and y = - 2/3x. Identify the value of x that simultaneously satisfies both equations.

Let's solve this by subst. (-2/3) x for y in y=2x+8.

Then 2x+8 = (-2/3) x. (For clarity you must use those parentheses.)

The LCD is 3. Mult. both sides by 3, obtaining

6x+24 = - 2x. Then 8x = - 24, and x = - 3. Now that you have a value for x, subst. this value (-3) into either of the given equations to determine y.

Then write your solution in the form (-3,?).